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Tutors Answer Your Questions about Age Word Problems (FREE)
Question 132273: A truck loaded with vegetables left Station B at 5:00 am and traveled eastward towards town M running at an average speed of 30 kph. At the same time, an express
bus left Station A, 30 km west of Station B, and traveled eastward towards town M
running at an average speed of 50 kph. When will the bus overtake the truck?
Click here to see answer by nycsharkman(136)  |
Question 132274: A truck loaded with vegetables left Station B at 5:00 am and traveled eastward towards town M running at an average speed of 30 kph. At the same time, an express
bus left Station A, 30 km west of Station B, and traveled eastward towards town M
running at an average speed of 50 kph. When will the bus overtake the truck?
Click here to see answer by nycsharkman(136)  |
Question 132272: Tony is half as old as Ric,Pete is 4 years younger than Ric and Don is 3 times as old as Tony. The sum of the ages of Tony and Ric 5 years hence is equal to the sum of the ages of Don and Pete 3 years ago. Find their present ages.
Click here to see answer by josmiceli(3007)  |
Question 133068This question is from textbook
: how whould i set up an equation for this word problem
four years ago, katie was twice as old as anne was then. in 6 years, anne will be the same age that katie is now. how old is each now?This question is from textbook
Click here to see answer by solver91311(5072)  |
Question 133181: I have three word problems for age and I know that they are simple but I can't seem to find the correct formula
1. If John is x years old and Julia is 4 years younger, what age does Alfred have in each case?
a) Alfred is 1 year older than the average age of John and Julia.
b) Alfred is 2 years younger than 5 times the difference of John's and Julias ages.
This math text is in Spanish so I translated the problems into English.
2. A father is 3 times as old as his son. In 12 years he will be double the age of his son. What are the father and son's ages now?
Click here to see answer by stanbon(26268)  |
Question 134086: Anne is now seven times as old as joan.In six years ann will be five times as old as joan.find the age of each one.
Let a=Anne's age j=Joan's age
a = 7j now.------------(1)
In 6 yrs, a+6 =5(j+6)---(2)
(2)-(1): 6= 5(j+6)-6j==>
6=5j+30-7j =30-2j==>
j=24/2=12. Substitute j=12 in (1) to get a=7*12=84.
a= Anne's age=84 and j=joan's age =12
Click here to see answer by Ganesha(13)  |
Question 134131: Hello I am trying to find the solution to this problem about age. Im not sure if you divide or what steps you take to complete this problem.
I would think you divide 28 evenly...but i'm confused. Any help would be great!
Ralph is ten years older than his sister Rose. If the sum of their ages in three years is 28, how old are they now? Be sure to include all necessary work and the ages of each person.
Thank you very much for your time,
Mrs. Gibson
Click here to see answer by jojo14344(1483)  |
Question 134417: My problem : At a recent birthday party for a friend of mine, I pointed out the following to my friend: Thirteen years ago, you were half as old as you will be five years from now. What was my friend's age?
I have no work to show on this one because the sample(below) shows that Im doing formula all wrong....Please help me see where I am going wrong. Its been a while and Im obviously close but too rusty :P
SAMPLE: At a recent birthday party for a friend of mine, I pointed out the following to my friend: Eighty-eight years ago, you were one-third as old as you will be six years from now.
My answer: 123 correct answer was 135
Sample problem solutions 88+6=94/3=31+94=125 or 88/3=29+88+6=123
Thank you really for taking the time having done tutoring myself I appreciate what you guys are doing here.
Click here to see answer by vleith(1977)  |
Question 134417: My problem : At a recent birthday party for a friend of mine, I pointed out the following to my friend: Thirteen years ago, you were half as old as you will be five years from now. What was my friend's age?
I have no work to show on this one because the sample(below) shows that Im doing formula all wrong....Please help me see where I am going wrong. Its been a while and Im obviously close but too rusty :P
SAMPLE: At a recent birthday party for a friend of mine, I pointed out the following to my friend: Eighty-eight years ago, you were one-third as old as you will be six years from now.
My answer: 123 correct answer was 135
Sample problem solutions 88+6=94/3=31+94=125 or 88/3=29+88+6=123
Thank you really for taking the time having done tutoring myself I appreciate what you guys are doing here.
Click here to see answer by jim_thompson5910(13787)  |
Question 134820: hi
i need your help on this one age problem that im stumped on
grandma is three years younger than grandpa and at their 30th anniversery, grandma was 17/18 of grandpa's age. how old were they when they got married?
thanks for your help
Click here to see answer by stanbon(26268)  |
Question 134832: hi
really need help...thanks a bunch
In five years annie's age will be one half of Sean's age. IN twelve years, one half of Annie's age will be one third of Sean's age. How old are they now?
thanks a lot
Click here to see answer by ptaylor(1578)  |
Question 130825: The sum of Carl's and Patricia's ages is 30. Thirteen years ago, Patricia was three times as old as Carl. How old is each now.
This is one of the many questions on my homework assignment. I have no clue how to figure out these problems. Please help me learn to set it up correctly.
Click here to see answer by awang1996(50)  |
Question 138992: A paleontologist discovers a fossil and wishes to determine its age. This can be done by measuring the amount of carbon-14 that is contained in the fossil. It is known that the decay of carbon-14 can be modeled with the exponential decay function . The paleontologist discovers that the fossil contains 70% of its original amount of carbon-14. Assume that the half-life of carbon-14 is 5600 years and determine the age of the fossil.
Click here to see answer by scott8148(3382)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530
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