|
Tutors Answer Your Questions about Age Word Problems (FREE)
Question 34097: chad has a total of 5 people in his family.
•Sally is Chad's twin sister.
•Chad's sister Hailey is 4 years older than Chad.
•Chad's mother was 24 when chad was born.
•Chad's father is 3 years older than his mother.
1.Write an expression for each family member's age as a function of Chad's age(x).
2.The average age of the 5 family members is 22. Determine the age of chad's sister Hailey.
Please help me as soon as possible... thank you very much!!!
Click here to see answer by 303795(562)  |
Question 65733: "How old are you?" Alex asked his cousin Gustav one day. "The day before yesterday," replied Gustav, "I was twice as old as my sister, but next year I will be three times as old as she is now." How old is Gustav? When is his birthday? On what day did this conversation take place? How old is Gustav's sister?
Click here to see answer by venugopalramana(3286)  |
Question 65733: "How old are you?" Alex asked his cousin Gustav one day. "The day before yesterday," replied Gustav, "I was twice as old as my sister, but next year I will be three times as old as she is now." How old is Gustav? When is his birthday? On what day did this conversation take place? How old is Gustav's sister?
Click here to see answer by Edwin McCravy(2922)  |
Question 66635This question is from textbook Beginning Algebra 
: What was the age 75 + population of Europe in 1995?
:
Population (in thousands)
1950 : 1970 : 1995
Age 0-14 : 143,175 : 166,367 : 139,464
:
Age 15-64 : 359,162 : 421,432 : 487,110
:
Age 65 + : 44,981 : 68,642 : 101,338
:
Age 75 + : 14,553 : 22, 762 : 38,139
:
Total : 547,318 : 656,441 : 727,912
_________________________________________________________________________________
What was the percentage increase in the age 75 + population of Europe from 1970 to 1995?
a)67.6%
b)63.4%
c)68.9%
d)65.1%
Any help with these two questions is greatly appreciated. Thanks
This question is from textbook Beginning Algebra 
Click here to see answer by Edwin McCravy(2922)  |
Question 75326: Can you please provide assistance in creating the equation for this problem and also show how to solve this word problem.
Problem: Edmund is 3 years older than Frank. The sum of their ages is nineteen years. How old is each one?
Click here to see answer by Earlsdon(4900)  |
Question 79354: My teacher gave me a worksheet with the following problem:
A population of turtles are t years is described by the function p(t)=175(1.145)^t. How long does it take for the population to triple?
We are working on logs and interest and I remember doing problems like this before but I am having trouble starting it.
Click here to see answer by stanbon(26268)  |
Question 79474: This problem I am having alot of trouble trying to figure out. Please Help!!
Mutt is half as old as Jeff will be when Mutt is twice as old as Jeff was when Mutt was half as old as Jeff is now. In five years, the sum of Mutt’s and Jeff’s ages will be 100. How old are Mutt and Jeff now?
Click here to see answer by ankor@dixie-net.com(6693)  |
Question 79474: This problem I am having alot of trouble trying to figure out. Please Help!!
Mutt is half as old as Jeff will be when Mutt is twice as old as Jeff was when Mutt was half as old as Jeff is now. In five years, the sum of Mutt’s and Jeff’s ages will be 100. How old are Mutt and Jeff now?
Click here to see answer by josmiceli(3007)  |
Question 79553: This is a problem my teacher made up and I'm getting stuck after I set up the table.
In a total of 2 hours, a tugboat traveled upriver 5 miles and returned. If the river's current is 4 miles per hour, find the speed of the tugboat in still water. Round your answer to the nearest 0.1 mi/hr if necessary.
Click here to see answer by stanbon(26268)  |
Question 82186: Dave's father is three times as old as Dave. In 10 years, he will be only twice as old as Dave. Hold old are they both now?
My Work:
Dave = x. Dave's dad = 3x. for the first sentence.
But that's all I get. I don't know where to go from there. Please help.
Click here to see answer by Edwin McCravy(2922)  |
Question 82784: PROBLEM
A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now?
________________________________________________________________________________
Woman= h+5
Husband= h
Daughter=h+5/10(I think)
+________
100
(h+5)+(h)+(h+5/10)=100
2h+5+(h+5/10)=100
3h+10=1000
3h/3=990/3
h=330
My question is what did i do wrong I know that this is way too high of a number and I can't figure out where I went wrong. Thanks
Click here to see answer by jim_thompson5910(13787)  |
Question 82784: PROBLEM
A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now?
________________________________________________________________________________
Woman= h+5
Husband= h
Daughter=h+5/10(I think)
+________
100
(h+5)+(h)+(h+5/10)=100
2h+5+(h+5/10)=100
3h+10=1000
3h/3=990/3
h=330
My question is what did i do wrong I know that this is way too high of a number and I can't figure out where I went wrong. Thanks
Click here to see answer by rapaljer(3620)  |
Question 82784: PROBLEM
A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now?
________________________________________________________________________________
Woman= h+5
Husband= h
Daughter=h+5/10(I think)
+________
100
(h+5)+(h)+(h+5/10)=100
2h+5+(h+5/10)=100
3h+10=1000
3h/3=990/3
h=330
My question is what did i do wrong I know that this is way too high of a number and I can't figure out where I went wrong. Thanks
Click here to see answer by stanbon(26268)  |
Question 82784: PROBLEM
A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now?
________________________________________________________________________________
Woman= h+5
Husband= h
Daughter=h+5/10(I think)
+________
100
(h+5)+(h)+(h+5/10)=100
2h+5+(h+5/10)=100
3h+10=1000
3h/3=990/3
h=330
My question is what did i do wrong I know that this is way too high of a number and I can't figure out where I went wrong. Thanks
Click here to see answer by scott8148(3382)  |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530
|
| |