SOLUTION: Five years ago a mother was twice as old as her son in six years time the sum of their ages will be 82. Find their present ages.

Question 999302: Five years ago a mother was twice as old as her son in six years time the sum of their ages will be 82. Find their present ages.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Five years ago a mother was twice as old as her son.
In six years time the sum of their ages will be 82.
Find their present ages.
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Equations:
m-5 = 2(s-5)
m+6 + s+6 = 82
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Rearrange::
m - 2s = -5
m + s = 70
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Subtract and solve for "s":
3s = 75
son's age = 25 yrs
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Solve for "m":
m + s = 70
mother's age = 55 yrs
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Cheers,
Stan H.
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