SOLUTION: the age of father exceeds to the square of the age of his son by 4 years. the sum of the age of father and four times the age of his son is 64 years. find their ages.
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Question 998811: the age of father exceeds to the square of the age of his son by 4 years. the sum of the age of father and four times the age of his son is 64 years. find their ages.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Let son be y years
father be x years
x= y^2+4
x+4y =64
substitute x
y^2+4+4y=64
y^2+4y-60=0
y^2+10y-6y+60=0
y(y+10)-6(y+10)=0
(y+10)(y-6)=0
y= 6 OR -10
discard -10
son's age = 6 years
Father's age = 40 years
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