SOLUTION: Jake is 5 years older than john. jill is twice as old as john. jan is 5 years younger than john. the sum of all the ages is equal to 75. find their ages.

Question 989927: Jake is 5 years older than john. jill is twice as old as john. jan is 5 years younger than john. the sum of all the ages is equal to 75. find their ages.

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
J=john's age; A=Jake's age=J+5; I=Jill's age=2J;
N=Jan's age=J-5
.
J+A+I+N=75
J+(J+5)+(2J)+(J-5)=75
5J=75
J=15
ANSWER 1: John is 15 years old.
A=J+5=15+5=20
ANSWER 2: Jake is 20 years old.
I=2J=2(15)=30
ANSWER 3: Jill is 30 years old.
N=J-5=15-5=10
ANSWER 4: Jan is 10 years old.

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