SOLUTION: My current age is 4 times what my sister's age was 20 years ago. I am now twice as old as I was 20 years ago. Ten years ago, my sister's age was 1/2 of my current age. Ten years ag
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Question 981839: My current age is 4 times what my sister's age was 20 years ago. I am now twice as old as I was 20 years ago. Ten years ago, my sister's age was 1/2 of my current age. Ten years ago, my age was 1.5 times my sister's age. What is my current age?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
y, my age
x, my sister's age
My current age is 4 times what my sister's age was 20 years ago.
I am now twice as old as I was 20 years ago.
Ten years ago, my sister's age was 1/2 of my current age.
Ten years ago, my age was 1.5 times my sister's age.
A few simple sentences forming a complicated description, but you should find that the
question to be answered will come from just one equation in the single variable, y.
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