SOLUTION: Maria is eight years old than precy ten years ago, the product of their age is 84. How to find the present?

Question 979713: Maria is eight years old than precy ten years ago, the product of their age is 84. How to find the present?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
let m = M's age
let p = P's age
:
write an equation for each statement
:
Maria is eight years older than precy
m = p + 8
ten years ago, the product of their ages was 84.
(m-10)*(p-10) = 84
Replace m with (p+8)
((p+8)-10)*(p-10) = 84
(p-2)*(p-10) = 84
FOIL
p^2 - 10p - 2p + 20 - 84 = 0
a quadratic equation
p^2 - 12p - 64 = 0
Factors to
(p+4)(p-16) = 0
two solutions, but we only want the positive solution
p = 16 yr is P's age
then
16 + 8 = 24 yrs is M's age
:
:
See if that checks out in the statement
"10 years ago, the product of their ages was 84."
(16-10)*(24-10) = 84

RELATED QUESTIONS
Cora is twice old as her sister Maria. The quotient of their ages five years ago was... (answered by MathTherapy)

ten years ago caridad was the same age as maria if the sum of their age now is 30 how old (answered by richwmiller,josgarithmetic)

rizza's age is one year more than twice norries's age. eight years ago, the sum of their... (answered by ankor@dixie-net.com)

Rizza's age is one year more than Norie's age. Eight years ago, the sum of their ages was (answered by mathstutor494)

Maria's age is M. Pat's age is M+3 five years ago. The product of their age was 70. How... (answered by stanbon)

Maria's age is M. Pat's age is M+3. Five years ago, the product of their ages was 70. How (answered by DrBeeee)

Charles is 4 years older than Jake. The product of Charles' age three years from now and (answered by ikleyn)

Today, Maria's age is six times than Ana's age ten years ago. Five years from now, Ana's... (answered by ankor@dixie-net.com)

the present age of three persons in proportions 4:7:9 Eight years ago the sum of their... (answered by Fombitz)