SOLUTION: five times a age exceeds b age by 5 years.1/9th of B age is the half of A ge find the ages
Algebra.Com
Question 976398: five times a age exceeds b age by 5 years.1/9th of B age is the half of A ge find the ages
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Small form or capital form, make you choice and stick with it through the problem description.
Ages r and s;
Solve the system for r and s.
RELATED QUESTIONS
Five years ago A age was four times the age of B. Five years hence A age will be the age (answered by Boreal)
Five years ago, A's age was four times B's age, 6 years hence A's age to B's is 5:2. Find (answered by Maths68)
Five years ago. A's age was four times B's age, 6 years hence A's age to B's is 5:2. Find (answered by Maths68)
The Sum of the ages of A and B is 42 years.
3 years back, the age of A was 5 times... (answered by Maths68)
A says to B "my present age is five times of your age when i was as old as you are now."... (answered by ankor@dixie-net.com)
Four times B’s age exceeds A’s age by 20 years,and one third of A’s age is less than B’s... (answered by josgarithmetic)
The age of A is 1/3 the age of B, 15 years ago the age of A was 1/6 the age of B. Find... (answered by jorel1380)
the age of father exceeds to the square of the age of his son by 4 years. the sum of the... (answered by mananth)
If twice the present age of Pedro is decreased from Petra's age 5 years ago, the result... (answered by josgarithmetic)