SOLUTION: bobs ages four times greater than Susan's age Dakotas three years younger than Susan the sum of Bob Susan's and Dakotas age is 93 what is Susan's age?

Question 970894: bobs ages four times greater than Susan's age Dakotas three years younger than Susan the sum of Bob Susan's and Dakotas age is 93 what is Susan's age?

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
let b= Bob's age
let s Sue's age
let d = Dak's age
:
write an equation for each statement
:
bobs ages four times greater than Susan's age
b = 4s
:
Dakotas three years younger than Susan
d = s - 3
:
the sum of Bob Susan's and Dakotas age is 93
b + s + d = 93
:
what is Susan's age?
Substitute 4s for b and (s-3) for d, in the above equation
4s + s + (s-3) = 93
6s = 93 + 3
6s = 96
s = 96/6
s = 16 yrs is Sue's age
:
:
You can check this for yourself, find b and d and see if the sum is 93

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