SOLUTION: 9 men do a piece of work in 28 days.
(a). How long will it take 14 men to do it?
(b). How many men will do it in 56 days?
Algebra.Com
Question 956640: 9 men do a piece of work in 28 days.
(a). How long will it take 14 men to do it?
(b). How many men will do it in 56 days?
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
9 men do a piece of work in 28 days.
# of men and # of days are inversely related::
----
d = k/m
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Solve for "k" using the data above::
28 = k/9
k = 252
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Equation::
d = 252/m
(a). How long will it take 14 men to do it?
d = 252/14 = 18 days
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(b). How many men will do it in 56 days?
56 = 252/m
m = 252/56
m = 4.5 men
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Cheers,
Stan H.
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Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
To do 1 job takes man-days
----------------------------
(a)
I can say:
1 job takes man-days
14 men will take 18 days
---------------------------
(b)
1 job takes
4.5 men will take 56 days
====================
You can do this another way:
9 men do a piece of work in 28 days.
1/3 as many men takes 3 times as long, so
3 men take 84 days
7 times as many men take 1/7 times as long, so
21 men take 12 days
twice as many men take 1/2 this time, so
42 men take 6 days
1/3 as many men take 3 times as long, so
14 men take 18 days to do the job
--------------------------------------
This is just an example of what you might do
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