SOLUTION: Marion is five years younger than Susan In 10 years susan will be three times as old as Marion was three years ago. Find their present ages

Question 953995: Marion is five years younger than Susan
In 10 years susan will be three times as old as Marion was three years ago. Find their present ages
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Marion is five years younger than Susan
In 10 years susan will be three times as old as Marion was three years ago. Find their present ages
let x=
3 yrs ago:
x-5-3=x-8=Marian's age
In ten years:
x+10=Susan's age
x+10=3(x-8)
x+10=3x-24
2x=34
x=17
x-5=12
Susan's age=17
Marion's age=12
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