SOLUTION: Suppose the ages of two siblings are consecutive odd integers. If the product of their ages is 35, what is the age (in years) of the younger sibling? (Enter an exact number.)

Question 951961: Suppose the ages of two siblings are consecutive odd integers. If the product of their ages is 35, what is the age (in years) of the younger sibling? (Enter an exact number.)

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
y=younger; y+2=older
(y)(y+2)=35
y^2+2y-35=0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=144 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 5, -7. Here's your graph:

ANSWER The age of the younger sibling is 5.
y+2=5+2=7 The older sibling is 7.
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