SOLUTION: A father is four times as old as his daughter. The sum of the squares of their ages is 1088. Find their ages.
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Question 951594: A father is four times as old as his daughter. The sum of the squares of their ages is 1088. Find their ages.
Found 2 solutions by macston, ankor@dixie-net.com:
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
d=daughter's age; 4d=father's age
Divide each side by 17
Find the square root of each side
d=8 ANSWER 1: The daughter is 8 yeras old.
4d=4(8)=32 years ANSWER 2: The father is 32 years old.
CHECK:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
let f = father's age
let d = daughter's age
:
Write an equation for each statement
:
A father is four times as old as his daughter.
f = 4d
:
The sum of the squares of their ages is 1088. Find their ages.
f^2 + d^2 = 1088
replace f with 4d
(4d)^2 + d^2 = 1088
16d^2 + d^2 = 1088
17d^2 = 1088
d^2 = 1088/17
d^2 = 64
d =
d = 8 yrs is the daughter's age
I'll let you find Dad's age, check your solutions in the 2nd equation
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