SOLUTION: A father is now 7 times as old as his son in 5 years he will be 4 times as old as his son will be then. what are their present ages?

Question 945028: A father is now 7 times as old as his son in 5 years he will be 4 times as old as his son will be then. what are their present ages?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A father is now 7 times as old as his son in 5 years he will be 4 times as old as his son will be then. what are their present ages?
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f = 7s
f+5 = 4(s+5)
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Substitute and solve for "f":::
7s + 5 = 4s + 20
3s = 15
s = 5 yrs (son's age now)
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Solve for "f"::
f = 7s
f = 35 yrs (father's age now)
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Cheers,
Stan H.
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