SOLUTION: if 7 apples and 2 oranges costs 114 while 6 apples and 4 oranges cost 132, how much does one apple and one orange cost?

Question 939041: if 7 apples and 2 oranges costs 114 while 6 apples and 4 oranges cost 132, how much does one apple and one orange cost?
Found 2 solutions by josgarithmetic, lwsshak3:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
a, price for one apple
n, price for one orange

Two linear equations in two unknown variables. Need more help?
If you simplify the "132" equation, you can easily use Elimination Method...
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
if 7 apples and 2 oranges costs 114 while 6 apples and 4 oranges cost 132, how much does one apple and one orange cost?
Your total cost in dollars for apples and oranges is a bit high, so I will use reasonable costs of $11.40 and $13.20 instead.
***
let a=cost of one apple
let o=cost of ome orange
..
7a+2o=11.40
6a+4o=13.20
..
14a+4o=22.80(mult. eq by 2)
6a+4o=13.20
subtract:
8a=9.60
a=1.20
2o=11.40-7a=11.40-8.40=3.00
o=1.50
cost of one apple=$1.20
cost of one orange=$1.50
These are very expensive apples and oranges

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