13 ≤ A ≤ 19, 13 ≤ B ≤ 19
B = A-3, so we substitute A-3 for B and 13 ≤ B ≤ 19 becomes 13 ≤ A-3 ≤ 19 We add 3 to all three sides: 16 ≤ A ≤ 22, but since A ≤ 19, 16 ≤ A ≤ 19
So A is a multiple of 3 and the only multiple of 3 between 16 and 19 is 18, so A = 18 and B = A-3 = 18-3 = 15. Edwin