SOLUTION: Mr. alvarado is 20 years older than his son. In 5 years, he will be 5 years more than twice as old as his son will then be. find the present ages.

Question 936901: Mr. alvarado is 20 years older than his son. In 5 years, he will be 5 years more than twice as old as his son will then be. find the present ages.

Answer by srinivas.g(540) (Show Source): You can put this solution on YOUR website!
let x,y be the present ages of Mr. alvarado and his sons
Mr. alvarado is 20 years older than his son.
hence
x= y+20..........eq(1)
In years , alvarado age will be = x+5
his son's age = y+5
In 5 years, he will be 5 years more than twice as old as his son
(x+5)= 2(y+5)+5
x+5 = 2*y+2*5 +5
x+5 = 2y+10+5
x+5= 2y+15
x= 2y+10
but x= y+20 from eq(1)
2y+10 =y+20
2y-y+10 =20
y+10 = 20
y= 10
present age of son = 10
present age of alvarado = 10+20 =30 years

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