SOLUTION: David was 25 when his daughter was born. Now his age exceeds 4 times his daughter's age by 10 years. How old are they now?

Question 936892: David was 25 when his daughter was born. Now his age exceeds 4 times his daughter's age by 10 years. How old are they now?
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
David was 25 when his daughter was born.

That means David is always 25 years older than his daughter.

David's age now = Daughter's age now + 25

Let daughter's age now = x
Then David's age now = x+25

Now his age exceeds 4 times his daughter's age by 10 years.

x + 25 = 4x + 10

Solve that to get daughter's age and then add 25 to get David's age.

Edwin

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