SOLUTION: Martin is two years younger then angel while janessa is triple angel's age. If the sum of their ages is seventy-eight, how old are they?

Question 936532: Martin is two years younger then angel while janessa is triple angel's age. If the sum of their ages is seventy-eight, how old are they?
Found 2 solutions by TimothyLamb, stanbon:
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = martin age
y = angel age
z = janessa age
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x = y - 2
z = 3y
x + y + z = 78
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put the system of linear equations into standard form
---
x - y = -2
3y - z = 0
x + y + z = 78
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
solution:
x = martin age = 14
y = angel age = 16
z = janessa age = 48
---
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Martin is two years younger then angel while janessa is triple angel's age. If the sum of their ages is seventy-eight, how old are they?
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Equations:
m = a -2
j = 3a
m + a + j = 78
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Substitute for "m" and "j" and solve for "a"::
a-2 + a + 3a = 78
5a = 80
a = 16 (angel's age now)
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m = a-2 = 14 (martin's age now)
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j = 3a = 48 (angel's age now)
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Cheers,
Stan H.
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