SOLUTION: Marvin is 3 more than twice the age of Anthony. In 10 years , the sum of their ages will be 47. How old are they now ?

Algebra.Com
Question 936172: Marvin is 3 more than twice the age of Anthony. In 10 years , the sum of their ages will be 47. How old are they now ?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
x Anthony's age. Marvin 2x+3
In 10 years...
2x +13 + x+10 = 47
3x = 24
x = 8, Anthony's age. Marvin 19
And...checking...In 10 years...
29 + 18 = 47

RELATED QUESTIONS

Romnick is 3 more than twice the age of Levin. In 10 years, the sum of their ages will be (answered by macston)
Mary is 3 more than twice the age of Anthony.In 10 years,the sum of their ages will be... (answered by leslielai89,josgarithmetic)
[ana is 5 years older than kristine. in 10 years, kristine's age is 24 more than the... (answered by TimothyLamb)
1. Ayie is 8 years older than Icas. The sum of their ages is 32. How old is each now? 2. (answered by mananth)
Bill is three years older than Ted. In five years, the sum of their ages will be 47. How... (answered by JulietG)
Steve is two years older than Marvin, Five years ago the sum of their ages was 10 years... (answered by josgarithmetic)
jennifer is 5 years more than twice bob's age. in 6 years the sum of their ages will be... (answered by ewatrrr)
Ana is 24 years older than twice the age of her younger sister. In ten years, their... (answered by ankor@dixie-net.com)
eric is two years older than his wife canoy. in 15 years, the sum of their ages will be 1 (answered by ankor@dixie-net.com)