Let:
F = father's age
M = mother's age
S = son's age
D = each of the twin daughter's age
>>Our family of two adults and three children is exactly 123 years<<
F+M+S+2D = 123
>>The father and son’s ages, when added are 59,<<
F+S = 59
which [59] is 5 years less than the mother and the twin girls.
59 = M+2D-5
64 = M+2D
>>The father is three years older than the mother,<<
F = M+3
>>the son is three years older than the girls.<<
S = D+3
So we have this system of 5 equations in 4 unknowns.
That means we were given more information that we needed.
Substitute D+3 for S in the first 4 equations and simplify:
Substitute M+3 for F in the first 3 equations and simplify:
Solve the middle equation for M: M=53-D. Substitute in the
other 2 equations:
So the twin daughters are 11 each.
M=53-D = 53-11 = 42, so the mother is 42.
F=M+3 = 42+3 = 45, so the father is 45.
S=D+3 = 11+3 = 14, so the son is 14.
Edwin