SOLUTION: three brothers have ages that are consecutive odd intergers. the difference between the age of the oldest and twice the age of the youngest is twenty four less than the middle brot
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Question 934957: three brothers have ages that are consecutive odd intergers. the difference between the age of the oldest and twice the age of the youngest is twenty four less than the middle brothers age. find their ages
Answer by vicgonzerx(31) (Show Source): You can put this solution on YOUR website!
X=YOUNGEST
X+2=MIDDLE
X+4=OLDEST
X+4-2X=X+2-24
2X=26
X=13
X+2=15
X+4=17
THE AGE ARE 13,15,17
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