SOLUTION: a boy is 10 years older than his brother. in four years, he will be twice as old as his brother. find the present age of each

Question 926788: a boy is 10 years older than his brother. in four years, he will be twice as old as his brother. find the present age of each
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = boy age
y = brother age
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x = y + 10
x + 4 = 2(y + 4)
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put the system of linear equations into standard form
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x - y = 10
x + 4 = 2y + 8
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x - y = 10
x - 2y = 4
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = boy age = 16
y = brother age = 6
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Solve and graph linear equations:
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Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php)
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