SOLUTION: John is twice Joan's age. 5 years ago he was 7 times her age. How old will each be next year?

Question 925878: John is twice Joan's age. 5 years ago he was 7 times her age. How old will each be next year?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = john age now
y = joan age now
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x = 2y
x - 5 = 7(y - 5)
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x = 2y
x - 5 = 7y - 35
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x - 2y = 0
x - 7y = -30
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put the system of linear equations into standard form
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x - 2y = 0
x - 7y = -30
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = 12
y = 6
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answer:
x = john age next year = 13
y = joan age next year 7
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Solve systems of linear equations up to 6-equations 6-variables:
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