SOLUTION: A man is twice as old as his son. If 9 years ago the sum of their ages was 66 years, what is their present ages.

Question 919889: A man is twice as old as his son. If 9 years ago the sum of their ages was 66 years, what is their present ages.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A man is twice as old as his son. If 9 years ago the sum of their ages was 66 years, what is their present ages.
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Equations::
f = 2s
f-9 + s-9 = 66
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Substitute for "f" and solve for "s"::
2s-9 + s - 9 = 66
3s - 18 = 66
3s = 84
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s = 28 son's age now
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f = 2s = 56 father's age now
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Cheers,
Stan H.
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