SOLUTION: Ten years ago, Alfred's age was three times that of his son Jerry. Fifteen years from now, Alfred's age will be twelve less than twice of Jerry's age. How old are they now?

Question 919049: Ten years ago, Alfred's age was three times that of his son Jerry. Fifteen years from now, Alfred's age will be twelve less than twice of Jerry's age. How old are they now?
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

years ago 's age was times that of his son .
.........eq.1
years from now 's age will be less than twice of age
.........eq.2
solve the system:
.........eq.1
.........eq.2
___________________________
.........eq.1 solve for

.......substitute in eq.2

.........eq.2..solve for

find

check:
years ago 's age was and 's age was
as you can see, is times times more than

years from now 's age will be and 's age will be
than twice of age is and

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