SOLUTION: on interchanging the digits of a two digit number(10x+y) is 37 less the original number.

Algebra.Com
Question 918174: on interchanging the digits of a two digit number(10x+y) is 37 less the original number.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
x and y Integers
10x + y - 37 = 10y + x
9x - 9y = 37 Cannot happen x - y ≠ 37/3

RELATED QUESTIONS

The digit at ten's place of a two-digit number is three times the digit at unit's place.... (answered by mananth)
The sum of digits of a two-digit number is 9. On interchanging the order of the... (answered by math_helper)
The tens digit of a certain two digit number is two more than the units digit. The... (answered by mathstutor458,richwmiller)
A certain two digit number is 13 more than 9 times the tens digit. The original number is (answered by lwsshak3)
A certain two digit number is 4 more than 10 times the tens digit. The original number is (answered by Boreal)
in a two digit number ,ten's digit is twice the unit's digit.the number formed by... (answered by josgarithmetic)
The number obtained after interchanging the digits of a two digit number is greater than... (answered by luke94,Alan3354)
In a two-digit number, ten's digit is twice the units digit. The number formed by... (answered by ankor@dixie-net.com)
In a two digit number one digit is even. Sum of original number and number obtained by... (answered by ankor@dixie-net.com)