SOLUTION: Allen is three times as old as Betty, and Luz is five years younger than Allen. Three years ago, the sum of their ages was 56 years. What are their present ages? Show a solution.

Question 909175: Allen is three times as old as Betty, and Luz is five years younger than Allen. Three years ago, the sum of their ages was 56 years. What are their present ages?
Show a solution.
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
If 3 years ago, the sum was 56, then their present sum is 56+3+3+3 = 65.
A + B + L = 65
B = A
L = A-5
Take the known values from the bottom equation and put them into the top
A + B + L = 65
A +A + (A-5) = 65
2A - 5 = 65
2A = 70
Divide each side by 2
A = 30
If Allen is 30, then Betty is 10, and Luz is 25
RELATED QUESTIONS
Allen is 3 times as old as Betty. Catherine is 5 yrs younger than Allen. 3 yrs ago sum of (answered by Earlsdon)

Allen is three times as old as Sarah. Sarah is two years younger than jim , who is... (answered by nic0le116)

Alice is 4 years younger than Betty and Carl is 3 times as old as Alice. Five years ago,... (answered by solver91311)

Suasan is three times as old as nancy, and Carrie is 5 years younger than Susan. Three... (answered by stanbon)

Pls. help me with my assignment... Anna is twice as old as Melody. Five years ago, Anna... (answered by awang1996)

Marion is five years younger than Susan In 10 years susan will be three times as old as... (answered by lwsshak3)

A father is three times as old as his son, and his daughter is 3 years younger than the... (answered by addingup)

Pam is eight years younger than Jim. In one year Jim will be three times as old as Pam... (answered by josmiceli)

Mickey is eight years younger than Minnie. In one year, Minnie will be three times as old (answered by ankor@dixie-net.com)