SOLUTION: Ten years ago, father was 12 times as old as his son and ten years hence,he will be twice as old as his son.Find their present age.
Algebra.Com
Question 909108: Ten years ago, father was 12 times as old as his son and ten years hence,he will be twice as old as his son.Find their present age.
Answer by clearblueskai(22) (Show Source): You can put this solution on YOUR website!
Ten years ago, father was 12 times as old as his son and ten years hence,he will be twice as old as his son.Find their present age.
x= father's present age
y= son's present age
10 years ago:
10 years from now:
Ten years ago, father was 12 times as old as his son:
Ten years hence, he will be twice as old as his son:
System of equations:
Eliminate one variable
+ =
Plug in the value of y to any of the equations:
RELATED QUESTIONS
.A father is twice as old as his son. 20 years ago, the age of the father was 12 times... (answered by josgarithmetic)
A father is twice as old as his son. Ten years ago he was three times as old as his son.
(answered by ankor@dixie-net.com)
Ten years ago a father was seven times as old as his son, two years hence twice
his age... (answered by vleith)
Ten years ago a father was seven times as old as his son, two years hence twice
his age... (answered by ankor@dixie-net.com)
1. presently, the ages of a father and his son are 10x and x years respectively. In 32... (answered by ankor@dixie-net.com)
Ten years ago a father was seven times as old as his son, two years hence twice his age... (answered by ankor@dixie-net.com)
ten years ago a father was six time as old as his son. After 10 years, he will be twice... (answered by stanbon)
Five years ago, a father was seven times as old as his son. Five years hence, the father... (answered by fractalier)
Five years ago a father was thrice as old as his son. Fifteen years hence he will be... (answered by ankor@dixie-net.com)