SOLUTION: The age of a father and son adds up to 37 and the mother's age is 5 times that of the son's .If mom's age is 7 years less than that of the father's, what is the mother age?

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Question 907506: The age of a father and son adds up to 37 and the mother's age is 5 times that of the son's .If mom's age is 7 years less than that of the father's, what is the mother age?
Found 2 solutions by AlgebraLady88, MathTherapy:
Answer by AlgebraLady88(44)   (Show Source): You can put this solution on YOUR website!
The age of a father and son adds up to 37.
The equation for this would be f+s = 37
The mother's age is 5 times that of the son's
The equation for this would be m= 5s
Mom's age is 7 years less than the father's.
This equation would be m= f-7
Father's age is m+7 = f
Plug this into f+s= 37
(m+7) + s = 37
If m= 5s, then (m+7) + s = 37
5s + 7 + s = 37
6s + 7 = 37
6s = 30
s = 5
This is the son's age.
If s = 5, then f+s = 37 will give us the father's age
f+5 = 37
f = 32
If s= 5, then m=5s gives us the mother's age
m= 5(5)
m= 25
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The age of a father and son adds up to 37 and the mother's age is 5 times that of the son's .If mom's age is 7 years less than that of the father's, what is the mother age?


Let mother’s age be M

Then son’s is: , or 

Father’s is: M + 7

We then have: 

5M + 35 + M = 185 ------- Multiplying by LCD, 5

5M + M = 185 – 35

6M = 150

M, or mother’s age = , or  

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