SOLUTION: I am having trouble figuring out how to set up this problem. Thank you in advance to anyone who helps! Addison is 3 times as old as Bailey and Bailey is 2.5 times as old as Chris

Question 905890: I am having trouble figuring out how to set up this problem. Thank you in advance to anyone who helps!
Addison is 3 times as old as Bailey and Bailey is 2.5 times as old as Christopher. If the sum off all of their ages is 66, how old is Christopher?
Found 2 solutions by ewatrrr, Fombitz:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
x Christopher's age
Addison + Bailey + Christopher
3(2.5x) + (2.5x) + x = 66
7.5x + 2.5x + x = 66
11x = 66
x = 6, Christopher's age, Bailey is 15 and Addison is 45
And...
sum = 66

Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

From eq. 2,

Substitute,

Now that you know Bailey's age, work backwards to find Addison and Christopher's ages.
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