SOLUTION: Please help me to solve this problem . the sum of the ages of two children is 16 years . four years ago the age of the older child was three times the age of the younger child. fin

Question 903598: Please help me to solve this problem . the sum of the ages of two children is 16 years . four years ago the age of the older child was three times the age of the younger child. find the present age of each child
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
A + B = 16
(A-4) = 3(B-4)
Distribute
(A-4) = 3B-12
Add 4 to each side
A = 3B - 8
Substitute the value of A that you just calculated into the top equation.
A + B = 16
(3B-8) + B = 16
4B-8 = 16
Add 8 to each side
4B = 24
Divide each side by 4
B = 6
If the younger child is 6, then the older is 10 (16-6)

Prove it:
four years ago the age of the older child (10-4=6) was three times the age of the younger child (6-4=2)
6 = 3x 2
RELATED QUESTIONS
The sum of the ages of two children is 16 years. Four years ago, the age of the older... (answered by CubeyThePenguin)

I have been trying to solve this age problem: A boy's sister is 3 years younger than him. (answered by josgarithmetic,MathTherapy)

please help me solve this problem. jessie is 5 years older than ariane. four years from... (answered by stanbon)

please,help me solve this problem:The sum of the ages of a mother and her child is 63.if (answered by ikleyn)

Manny is 9 years older than Charlie. Four years ago the sum of their ages was 17 years.... (answered by macston)

Mrs. A has four children, namely, P, Q, R, and S. Q is currently twice the age of S.... (answered by ankor@dixie-net.com)

Please help me solve this age problem: The sum of Sonny and Cely's ages is 81. 3 years... (answered by benbjlin)

Please help me to solve this problem with the help of algebra equation. Thanks... (answered by CubeyThePenguin)