SOLUTION: The sum of 4 times Joan's age and 5 times Larry's age is 37. Larry is 1 year less than twice as old as Joan. What are their ages?
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Question 901859: The sum of 4 times Joan's age and 5 times Larry's age is 37. Larry is 1 year less than twice as old as Joan. What are their ages?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
4J + 5(2J-1) = 37
14J = 42
J = 3, Joan's age. Larry is 5.
And...
12 + 25 = 37
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