SOLUTION: Jack is 3 times as old as Lacy. 4 years from now the sum of their ages will be 68. How old are they now?

Algebra.Com
Question 900359: Jack is 3 times as old as Lacy. 4 years from now the sum of their ages will be 68. How old are they now?

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
Lacy's age: x
Jack's age: 3x
(3x+4) + (x+4)= 68
4x = 60
x = 15, Lacy's Age NOW. Jack is 45
Ans..4 years from now..
49 + 19 = 68
RELATED QUESTIONS

Jack is 3 times as old as Lacy. 10 years from now the sum of their ages will be (answered by josgarithmetic)
Jack is 4 times as old as Lacy. 8 years from now the sum of their ages will be 81 . How (answered by graphmatics)
Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 67. How... (answered by stanbon)
Jack is 4 times as old as Lacy. 6 years from now the sum of their ages will be 87. How... (answered by Cromlix)
Jack is 4 times as old as Lacy. 9 years from now the sum of their ages will be 63. How... (answered by addingup)
Jack is 4 times as old as Lacy. 8 years from now the sum of their ages will be 76. How... (answered by josmiceli)
Jack is 4 times as old as lacy. 5 years from now the sum of their ages will be 85. How... (answered by Cromlix)
Jack is 3 times as old as Lacy. 9 years from now the sum of their ages will be 70 . How (answered by JBarnum)
jack is 3 times as old as Lacy. 10 years from now the sum of their ages will be 60. How... (answered by lwsshak3)