SOLUTION: Abigail is 28 years younger than her mother Bethany. the sum of their ages is 66 . how old is each now
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Question 894973: Abigail is 28 years younger than her mother Bethany. the sum of their ages is 66 . how old is each now
Answer by harpazo(655) (Show Source): You can put this solution on YOUR website!
Let A = Abigail
Let B = Bethany
A = B - 28
A + B = 66
B - 28 + B = 66
2B - 28 = 66
2B = 66 + 28
2B = 94
B = 94/2
B = 47.
Bethany is 47.
How old is Abigail?
Think for a minute.
If I subtract 47 from the total of their ages, I will know Abigail's age, right?
So, Abigail is 66 - 47 or 19.
Abigail is 19 and Bethany is 47.
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