SOLUTION: Mother's age is 6 times Gauri's age and grandmother's age is twice mother's age. After 5 years, the sum of their ages will be 110 years. Find their present age. Manju has $90 in

Question 886623: Mother's age is 6 times Gauri's age and grandmother's age is twice mother's age. After 5 years, the sum of their ages will be 110 years. Find their present age.
Manju has $90 in her piggy bank in $1 coins and 50 p coins. If the number of $1 coins is twice that of 50p coins, how many coins of each kind are there?
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
In the future, please post each problem individually. Multiple problem submissions tend to get overlooked. Thanks!
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Mother's age is 6 times Gauri's age and grandmother's age is twice mother's age. After 5 years, the sum of their ages will be 110 years. Find their present age.
M = 6G
N = 2M; therefore N = 12G
In 5 years, they will be 15 years old (5+5+5); therefore, the present sum of their ages = 110-15, or 95
M + G + N = 95
substitute the known values into that equation.
M + G + N = 95
(6G) + G + (12G) = 95
19G = 95
Divide each side by 19

If Gauri is 5 and mother is 6 times her age, Mother is
Grandmother is twice Mother's age, or
5 + 30 + 60 = 95
In five years, they will be 10 + 35 + 65, or 110
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Manju has $90 in her piggy bank in $1 coins and 50 p coins. If the number of $1 coins is twice that of 50p coins, how many coins of each kind are there?
72 dollars; 36 fifty pence

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