SOLUTION: The decay of 457mg of an isotope is given by A(t)=457e^-0.019t, where t is time in years. Find the amount left after 78 years.
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Question 881789: The decay of 457mg of an isotope is given by A(t)=457e^-0.019t, where t is time in years. Find the amount left after 78 years.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
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103.82 mg are left after 78 years
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