solve this: A is 3 times as old as B and B is 5 years older than C. If B is X years old write the algebraic expressions for following.
1. A is 3 times as old as B
A = 3B
2. B is 5 years older than C.
B = C+5
3. B is X
B = X
a) A's age todayFrom (1), A = 3B
From (3), B = X
Substituting X for B
A = 3X
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b) C's age todayFrom (2), B = C+5
From (3), B = X
Substitute X for B
X = C+5
Subtract 5 from both sides
X-5 = C
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c) A's age in 6 years timeSince from a), A = 3X
Add 6 to both sides:
A+6 = 3X+6
Answer: 3X+6
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d) The sum of A and B age in 4 years timeA is 3X now, so in four years, A will be 3X+4
B is X now so in four years, B will be X+4
In four years their sum will be
(3X+4)+(X+4) = 3X+4+X+4 = 4X+8
Answer: 4X+8
Edwin