SOLUTION: Bill and Jenna are solving the quadratic equation x 2 - x = 12. Bill solved this way Jenna solved this way x2 - x = 12 x(x - 1) = 12 x = 12 or 13 x2 - x = 12 x2 - x

SOLUTION: Bill and Jenna are solving the quadratic equation x 2 - x = 12. Bill solved this way Jenna solved this way x2 - x = 12 x(x - 1) = 12 x = 12 or 13 x2 - x = 12 x2 - x - 12 = 0

Question 879256: Bill and Jenna are solving the quadratic equation x 2 - x = 12.
Bill solved this way Jenna solved this way
x2 - x = 12
x(x - 1) = 12
x = 12 or 13 x2 - x = 12
x2 - x - 12 = 0
(x - 4)(x + 3) = 0
x = 4 or x = -3
Which student is correct?
What error did the other student make when solving?

Found 4 solutions by ewatrrr, Riley12, ikleyn, Alan3354:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
x^2 - x - 12 = 0
(x - 4)(x + 3) = 0
x = 4 or x = -3
What error did the other student make when solving?
being absent when factoring was explained?? don't know...
Quadratics are solved by using ,
by factoring Or by completing the square
Answer by Riley12(3)   (Show Source): You can put this solution on YOUR website!
The correct student is Jenna.
The error that Bill made when he was solving was that he used the zero product property incorrectly. The equation should be A*B=0, with the right side equaling 0 to work.
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.

There is no worst way to study and to teach Math as to consider and analyse the errors made by those

who does not know and can not do Math properly.

So, your exercise is waste of time.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
x2 - x = 12
Use ^ (shift 6) for exponents.
x^2 - x = 12
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