SOLUTION: 1 year ago a mother was four times older than her son. after 6 years her age become more than double her sons age by 5 years. what will be the ratio of their present age? plz

Question 866725: 1 year ago a mother was four times older than her son. after 6 years her age become more than double her sons age by 5 years. what will be the ratio of their present age?

plz answer this question...
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = mother's age now
Let = son's age now
= mother's age 1 year ago
= son's age 1 year ago
= mother's age in 6 years
= son's age in 6 years
------------------------------------------
(1)
(2)
------------------------------------
(1)
(1)
and
(2)
(2)
(2)
----------------------------
Add (1) and (2)
(2)
(1)

and, since
(1)
(1)
(1)
(1)
-----------------------
The mother is 25
The son is 7
-------------
check:
(2)
(2)
(2)
(2)
(2)
and
(1)
(1)
(1)
(1)
OK
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The other tutor's solution is probably the one expected, but,
4 times older = 5 times as old.
-----
Is 1 time older the same age?
4 times older = a 400% increase in age = 5 times as old.
Be careful of that.
-----
PS A thing can't be 10 times smaller, since 1 time smaller is zero.
This is what's known as GIBBERISH.
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