SOLUTION: Mary was twice as old as Ann was when Mary was as old as Ann. When Ann was as old as Mary, the sum of their ages is 180. How old are they now??

Question 856760: Mary was twice as old as Ann was when Mary was as old as Ann. When Ann was as old as Mary, the sum of their ages is 180. How old are they now??
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Mary was twice as old as Ann was when Mary was as old as Ann.
let d = the difference between their ages; m - a
m - d = 2(a - d)
m - d = 2a - 2d
m = 2a - 2d + d
m = 2a - d
m = 2a -(m-a)
m = 2a - m + a
m + m = 2a + a
2m = 3a
m = a
m = 1.5a
When Ann was as old as Mary, the sum of their ages is 180.
Ann is the younger so this does not make sense; maybe if it reads;
" When Ann IS as old as Mary, the sum of their age is 180"
Just looking at it I would say right now; m = 90, a = 60
When a = 90, then m = 120, a total of 180

How old are they now??
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