SOLUTION: a father is four times as old as his son ad his daughter is five years younger than her brother if their combined ages amount to 73 years find the age of each

Question 855351: a father is four times as old as his son ad his daughter is five years younger than her brother if their combined ages amount to 73 years find the age of each
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
F = 4S [a father is four times as old as his son]
S-5 = D [his daughter is five years younger than her brother]
F + D + S = 73 [their combined ages amount to 73 years]
.
Substitute the values into the last equation
F + D + S = 73
(4S) + (S-5) + S = 73
Add the Ss
6S - 5 = 73
Add 5 to each side
6S = 78
Divide each side by 6
S = 13
.
Now that you know the son's age, subtract 5 to get the daughter's (8), multiply that value by 4 to get the father's age (4*13=52).
52 + 13 + 8 = 73
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