SOLUTION: twice the age of son is 4 years more than the age of his father.findage of son if father is 40 years.
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Question 852451: twice the age of son is 4 years more than the age of his father.findage of son if father is 40 years.
Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
2S - 4 = F
F = 40
.
Simply substitute the value of F from the second equation into the first.
2S - 4 = 40
Add 4 to each side
2S = 44
Divide b 2
S = 22
.
Let's prove it.
Twice the age of the son (22 * 2 = 44) is 4 years older than his father (40).
44-4=40
success!
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