SOLUTION: One year ago,the father was 8 times as old as his son.Now his age is square of the son's age.Find their present ages. (By representing the situation in the form of a quadratic equa

Question 851156: One year ago,the father was 8 times as old as his son.Now his age is square of the son's age.Find their present ages. (By representing the situation in the form of a quadratic equation.)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
One year ago,the father was 8 times as old as his son.Now his age is square of the son's age.Find their present ages.
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F = S^2
(F-1) = 8*(S - 1) --> F = 8S - 7
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S^2 = 8S - 7

(S - 1)*(S - 7) = 0
S = 1 --> zero one year ago.
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S = 7
F = 49

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