SOLUTION: A father is 3 times as old as his son, eight years ago the father's age was 5 times that of his son. What are their present ages?
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Question 850629: A father is 3 times as old as his son, eight years ago the father's age was 5 times that of his son. What are their present ages?
Answer by hamsanash1981@gmail.com(151) (Show Source): You can put this solution on YOUR website!
Let the son's age be x then father's age = 3x
Eight years ago, their age will be x-8, 3x-8
3x-8 = 5(x-8)
3x-8 = 5x - 40
2x = 32
x = 16
Father's age = 48 and son's age = 16
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