SOLUTION: Find the area of a circle in which a chord AB is 48cm and the perpendicular bisector of the chord, originating at the centre of the circle, is 10cm.

Question 847874: Find the area of a circle in which a chord AB is 48cm and the perpendicular bisector of the chord, originating at the centre of the circle, is 10cm.
Answer by hamsanash1981@gmail.com(151) (Show Source): You can put this solution on YOUR website!
Let the center of the circle be O and O be the point at which it bisects the chord AB such that OPA forms the right angled triangle and OA is radius of the circle then OP = 10cm and AP = 24
By Pythagoras theorem,

OA = 26
RADIUS = 26
AREA = 22/7*26*26
=2124.57 Sq cm

RELATED QUESTIONS
Find the area of a circle in which a chord AB is 48 cm and the perpendicular bisector of... (answered by macston)

In the figure, ACB is an arc of a circle, and CD is the perpendicular bisector of chord... (answered by ikleyn)

A circle has a chord of length 10 cm. This chord is the perpendicular bisector of a... (answered by robertb)

A chord of length 16 sqrt3 is the perpendicular bisector of the radius in a circle.... (answered by ankor@dixie-net.com)

A line segment has points a (-4, 3) and be (3, -4). Show that ab is a chord of the circle (answered by Alan3354)

OAB is a sector of a circle, center O, radius 8 cm. Angle AOB=56�. M is the midpoint of (answered by mananth)

/AB/ is a chord of a circle of radius 10cm,M is the mid-point of /AB/ and /NM/... (answered by ikleyn)

Given a circle with radius 5cm and chord AB, measuring 6cm, find the perpendicular... (answered by ramkikk66)

In a circle of radius 13 cm the length of its chord is 10 cm. Find the perpendicular... (answered by josgarithmetic)