SOLUTION: a father is twice as old as his son..20 years before,the father was four times as old as his son. find their present age
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Question 841531: a father is twice as old as his son..20 years before,the father was four times as old as his son. find their present age
Answer by Narsinghchauhan8960103366(17) (Show Source): You can put this solution on YOUR website!
Let his son's present age = x years
So his father's present age = 2x years
Before 20 years his son's age=(x-20) years
Before 20 years father's age=(2x-20) years
4(x-20)=(2x-20)
4x-80=2x-20
4x-2x=80-20
2x=60
x=30
His son's present age = 30
Father's present age=60
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