SOLUTION: Amother is 4 times older then her son 5 years ago the product of thier ages was 175 find thier present ages

Question 840185: Amother is 4 times older then her son 5 years ago the product of thier ages was 175 find thier present ages

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Amother is 4 times older then her son 5 years ago the product of thier ages was 175 find thier present ages
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4 times older = 5 times as old.
M = 5S
(M-5)*(S-5) = 175
Sub for M
(5S-5)*(S-5) = 175
(S-1)*(S-5) = 35

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=156 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 9.2449979983984, -3.2449979983984. Here's your graph:

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The son is 9.245 years
Mom is 46.225 years
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The solution is not an integer because the author of the problem doesn't know the difference between 4 times as old and 4 times older.
Is 1 times older the same as 1 times as old?
Is 100% greater 1x as much? Or 2x?
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Don't ever mention "10 times smaller" since 1x smaller is zero.
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