SOLUTION: a man has a daughter and a son. Son is 3 years older than the daughter. In 1 years the father will be 6 times as old as daughter now and in 10 years he will be 14 years older tha
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Question 835040: a man has a daughter and a son. Son is 3 years older than the daughter. In 1 years the father will be 6 times as old as daughter now and in 10 years he will be 14 years older than combined ages of kids what is the mans age
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a man has a daughter and a son. Son is 3 years older than the daughter. In 1 years the father will be 6 times as old as daughter now and in 10 years he will be 14 years older than combined ages of kids what is the mans age
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Equations:
s = d + 3
f+1 = 6d
f+10 = (s+10) + (d+10) + 14
----
f+10 = (d+13) + d+10 + 14
f = 2d +13+14
f = 2d + 27
----
f+1 = 2d + 28
6d = 2d + 28
4d = 28
daughter = 7 yrs (now)
----
son = d+3 = 10 yrs (now)
father = 6d-1 = 41 yrs
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Cheers,
Stan H.
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Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = father's's age now
Let = son's age now
Let = daughter's age now
----------------------------
(1)
(2)
(3)
--------------------------------------
(2)
and
(3)
(3)
(3)
-----------------------
Substitute (1) and (2) into (3)
(3)
(3)
(3)
(3)
----------------
(2)
(2)
(2)
--------------
(1)
(1)
(1)
---------------
The father's age is 41
check:
(3)
(3)
(3)
(3)
OK
---------
(2)
(2)
(2)
OK
--------
(1)
(1)
(1)
OK
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