SOLUTION: In two years Andy will be as old as Joe now. In two years Joe will be 1 1/2 times as old as Andy is then. Find their ages now

Question 830404: In two years Andy will be as old as Joe now. In two years Joe will be 1 1/2 times as old as Andy is then. Find their ages now
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
---
x = Andy
y = Joe
---
x + 2 = y
y + 2 = 1.5(x + 2)
y + 2 = 1.5x + 3
---
put the system of linear equations into standard form:
---
x - y = -2
1.5x - y = -1
---
copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
solution:
x = Andy = 2
y = Joe = 4
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
RELATED QUESTIONS
in 2 years andy will be as old as joe is now. in 2 years joe will be 1 1/2 times as old... (answered by mananth,richwmiller)

Andy is twice as old as Kate. In 6 years, their ages will total 60. How old is Andy... (answered by stanbon)

Andy is four times as old as Wendy . In twelve years Wendy's age will be half of... (answered by algebrahouse.com)

elsie is twelve years old than her brother andy. four years from now andy will be two... (answered by robertb)

Andy is twice as old as Kate. In 6 years, their ages will total 60. How old is each... (answered by JBarnum)

Andy is twice as old as kate. In years, their ages will total 60. how old is each now? (answered by avani)

Andy is twice as old as kate in 6 years, their ages will toral 60 how old is each now (answered by Cromlix)

Andy is twice as old as Kate. In six years their ages will total 60. How old are they... (answered by ewatrrr)

Tom is twice as old as Andy. In 4 years time the sum of the ages will be 32 years. Find... (answered by amalm06,MathTherapy)